JetBlue Airways is launching twice-daily service between Boston Logan International Airport and Cleveland Hopkins International Airport on April 30.
The Ohio city of Cleveland will be JetBlue Airways’ 88th destination.
To promote the new service, the airline is offering an introductory one-way fare of $19.51. The number is a reference to the year that disc jockey Alan Freed made Cleveland famous by launching a rock ‘n’ roll and rhythm-and-blues program on local radio station WJW, bringing the music to the attention of millions of fans throughout the U.S. and then worldwide.
JetBlue Airways’ introductory fare, available in either direction on the Boston-Cleveland route, is available for travel between April 30 and June 18, 2015 , on Tuesdays, Wednesdays and Saturdays. All introductory-fare tickets much be purchased by December 10.
The airline’s schedule for its Boston-Cleveland service will see the first of the carrier’s two daily flights on the route leaving Boston Logan International Airport (IATA code BOS) at 6:45 a.m. from April 30 and reaching Cleveland Hopkins International Airport (CLE) at 8:50 a.m.
JetBlue’s second daily flight on the route will depart BOS at 4:10 p.m. and will land at CLE at 6:15 p.m.
In the other direction, JetBlue’s first flight of the day will leave CLE at 9:30 a.m. and touch down at BOS at 11:20 a.m. Its second flight will depart CLE at 6.55 p.m. and arrive at BOS at 8.45 p.m.
JetBlue Airways plans initially to serve Cleveland with 100-seat Embraer 190 jets, each of which has two-by-two seat configuration for all seat rows.